Compare Version Numbers as Tuples

Medium ⏱ 12 min 54% acceptance ★★★★☆ 4.3

Implement is_newer_version(v1, v2), where each version is a tuple of ints like (1, 4, 2) for major.minor.patch. Return True if v1 is strictly newer than v2, relying directly on Python's built-in lexicographic tuple comparison — no manual field-by-field if/elif chain.

Examples

Example 1

Input

is_newer_version((1, 4, 2), (1, 3, 9))

Output

True

Explanation

Minor version 4 beats 3, so v1 is newer regardless of the patch numbers.

Example 2

Input

is_newer_version((1, 4), (1, 4, 0))

Output

False

Explanation

(1, 4) is a strict prefix of (1, 4, 0) and Python treats the shorter prefix as smaller, so v1 is not newer.

Constraints

Tuples may have differing lengths.

Topics

TuplesComparison

Companies

MicrosoftAtlassian

Hints

Hint 1

Python compares tuples element by element and, on a matching prefix, the shorter tuple counts as smaller.

Hint 2

v1 > v2 does exactly this comparison.

← Zip Three Parallel Lists into Tuple Records Grab Head, Tail and Middle with Star-Unpacking →

Loading the Python runtime… Run executes your code and shows printed output; Submit checks your function against this problem's examples.